4c^2+24c+27=0

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Solution for 4c^2+24c+27=0 equation:


Simplifying
4c2 + 24c + 27 = 0

Reorder the terms:
27 + 24c + 4c2 = 0

Solving
27 + 24c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(9 + 2c)(3 + 2c) = 0

Subproblem 1

Set the factor '(9 + 2c)' equal to zero and attempt to solve: Simplifying 9 + 2c = 0 Solving 9 + 2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + 2c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + 2c = 0 + -9 2c = 0 + -9 Combine like terms: 0 + -9 = -9 2c = -9 Divide each side by '2'. c = -4.5 Simplifying c = -4.5

Subproblem 2

Set the factor '(3 + 2c)' equal to zero and attempt to solve: Simplifying 3 + 2c = 0 Solving 3 + 2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 2c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 2c = 0 + -3 2c = 0 + -3 Combine like terms: 0 + -3 = -3 2c = -3 Divide each side by '2'. c = -1.5 Simplifying c = -1.5

Solution

c = {-4.5, -1.5}

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